Section 1.2

Please post comments if you find any errors, or if you wish to contribute answers for additional problems. You may find information on using \LaTeX here.

1. (a) \displaystyle{a_n = \frac{1}{3^n}, n=0,1,2,\ldots}

(b) \displaystyle{a_n = \frac{1}{n}, n=1,2,3, \ldots}

(c) \displaystyle{a_n = \frac{2n+1}{n+1}, n=0,1,2,\ldots}

(d) \displaystyle{a_n = \frac{(-1)^n}{2n+1}, n=1,2,3,\ldots}

2. (a) Converges: \displaystyle{\lim_{n \to \infty}\frac{1}{3^n} = 0}

(b) Diverges: \displaystyle{\lim_{n \to \infty}\pi^n = \infty}

(c) Converges: \displaystyle{\lim_{n \to \infty}\frac{3n-1}{2n+6} = \frac{3}{2}}

(d) Diverges

(e) Diverges: \displaystyle{\lim_{n \to \infty}\frac{3n^4-6n^3+1}{5n^3+n^2+2}=\infty}

(f) Converges: \displaystyle{\lim_{n \to \infty}\frac{2n^5-3n^2+23}{7n^5+13n^4-12} =  \frac{2}{7}}

(g) Converges: \displaystyle{\lim_{n \to \infty}\frac{45-16n^2}{13+5n+6n^3} = 0}

(h) Converges: \displaystyle{\lim_{n \to \infty}\frac{3n+1}{\sqrt{4n^2+1}}=\frac{3}{2}}

(i) Diverges: \displaystyle{\lim_{n \to \infty}(-2)^{2n+1} = -\infty}

(j) Divergs: \displaystyle{\lim_{n \to \infty}\frac{10-16n^3}{1+n^2}=-\infty}

(k) Converges: \displaystyle{\sqrt{\frac{3n^2+n-6}{5n^2+16}}=\sqrt{\frac{3}{5}}}

(l) Converges: \displaystyle{\lim_{n \to \infty}\frac{(-1)^n}{5^n}=0}

3. \displaystyle{\lim_{n \to \infty}\frac{\sin(n)}{n}=0}

4. (a) a_1 = 2 , a_2 = 2.25 , a_3 = 2.3704 , a_4 = 2.4414 , and a_5 = 2.4883 , where the last three have been rounded to four decimal places.

(e) a_{74} > 2.7 , but a_n < 2.7 for n < 74 .

(f) n = 135

5. (e) n = 13

(f) n = 41

7. (c) \displaystyle{a_9 = a_{10} = \frac{1562500}{567}}

11. (a) \displaystyle{N = \left\lfloor \frac{1}{\epsilon}\right\rfloor} ; for \epsilon = 0.001 , N = 1000

(b) \displaystyle{N = \left\lfloor \frac{\log(\epsilon)}{\log(0.98)}\right\rfloor} ; for \epsilon = 0.001 , N = 341

(c) \displaystyle{N = \left\lfloor \frac{1}{\sqrt{\epsilon}}\right\rfloor} ; for \epsilon = 0.001 , N = 31

(d) \displaystyle{N = \left\lfloor \frac{1}{\sqrt[3]{\epsilon}}\right\rfloor} ; for \epsilon = 0.001 , N = 10

Leave a Reply