Section 3.6

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1. (a) Three solutions: -2.3407 , -0.9018 , 2.4080

(c) Two solutions: -0.8241 , 0.8241

(e) Two solutions 0.7135 , 2.0730

2. (d) If \displaystyle{L = \lim_{n \to \infty}x_n}, then
\displaystyle{L = \lim_{n \to \infty}x_{n+1} = \lim_{n \to \infty}\frac{x_n + \dfrac{c}{x_n}}{2} = \frac{L + \dfrac{c}{L}}{2}},
from which it follows that L^2 = c .

3. 1.25992

4. 1.25850

6. The values oscillate between 1 and -1 ; that is, for n = 0, 1, 2, \ldots , x_{2n} = 1 and x_{2n + 1} = -1 .

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