Comments for Difference Equations to Differential Equations http://de2de.wordpress.com Answers for selected problems Wed, 14 May 2008 14:39:01 +0000 http://wordpress.org/?v=MU Comment on Section 1.1 by Luisa Albergaria http://de2de.wordpress.com/2007/06/18/section-11/#comment-43 Luisa Albergaria Sun, 13 Jan 2008 14:15:29 +0000 http://de2de.wordpress.com/2007/06/18/section-11/#comment-43 I consider your documentation on Maths very good! I am going to teach people old. Thanks! I consider your documentation on Maths very good! I am going to teach people old.
Thanks!

]]> Comment on Section 1.1 by Luisa Albergaria http://de2de.wordpress.com/2007/06/18/section-11/#comment-42 Luisa Albergaria Sun, 13 Jan 2008 13:44:02 +0000 http://de2de.wordpress.com/2007/06/18/section-11/#comment-42 I am interested to teach some people of Agencia Portuguesa do Ambiente Thanks in advance for your atention I am interested to teach some people of Agencia Portuguesa do Ambiente
Thanks in advance for your atention

]]> Comment on Section 6.6 by cssp http://de2de.wordpress.com/2007/08/10/section-66/#comment-39 cssp Wed, 26 Dec 2007 19:26:21 +0000 http://de2de.wordpress.com/2007/08/10/section-66/#comment-39 That's right. Integrals can be tricky that way. Dan Sloughter That’s right. Integrals can be tricky that way.

Dan Sloughter

]]> Comment on Section 6.6 by Juan Manuel Barreneche http://de2de.wordpress.com/2007/08/10/section-66/#comment-38 Juan Manuel Barreneche Wed, 26 Dec 2007 19:15:53 +0000 http://de2de.wordpress.com/2007/08/10/section-66/#comment-38 sorry, i was wrong, log|sqrt(x² + 4)/2 + x/2| + C = log(|sqrt(x² + 4) + x|/2) + C = log|sqrt(x² + 4) + x| - log(2) + C = log|sqrt(x² + 4) + x| + C1 were C1 = C - log(2) JM sorry, i was wrong,

log|sqrt(x² + 4)/2 + x/2| + C
= log(|sqrt(x² + 4) + x|/2) + C
= log|sqrt(x² + 4) + x| - log(2) + C
= log|sqrt(x² + 4) + x| + C1
were C1 = C - log(2)

JM

]]> Comment on Section 6.6 by Juan Manuel Barreneche http://de2de.wordpress.com/2007/08/10/section-66/#comment-37 Juan Manuel Barreneche Wed, 26 Dec 2007 19:06:54 +0000 http://de2de.wordpress.com/2007/08/10/section-66/#comment-37 The answer for 1.e it's wrong: me and wolfram's integrator (http://integrals.wolfram.com/index.jsp) agree that the solution is log|sqrt(x² + 4)/2 + x/2| + C thank you, JM PD: The book it's great. The answer for 1.e it’s wrong: me and wolfram’s integrator (http://integrals.wolfram.com/index.jsp) agree that the solution is

log|sqrt(x² + 4)/2 + x/2| + C

thank you,

JM

PD: The book it’s great.

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